Evaluate (5^(2-3))/(20(3)+2(3))

$\frac{5^{2 - 3}}{20 (3) + 2 (3)}$

Move $5^{2 - 3}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{(20 (3) + 2 (3)) \cdot 5^{- (2 - 3)}}$

Simplify the denominator.

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Multiply $20$ by $3$ .

$\frac{1}{(60 + 2 \cdot 3) \cdot 5^{- (2 - 3)}}$

Multiply $2$ by $3$ .

$\frac{1}{(60 + 6) \cdot 5^{- (2 - 3)}}$

Add $60$ and $6$ .

$\frac{1}{66 \cdot 5^{- (2 - 3)}}$

Subtract $3$ from $2$ .

$\frac{1}{66 \cdot 5^{- - 1}}$

Multiply $- 1$ by $- 1$ .

$\frac{1}{66 \cdot 5^{1}}$

Evaluate the exponent.

$\frac{1}{66 \cdot 5}$

Multiply $66$ by $5$ .

$\frac{1}{330}$

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{330}$

Decimal Form:

$0.0\overline{03}$

Evaluate (5^(2-3))/(20(3)+2(3))

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