Factor 10k^2+23k+12

Math
10k2+23k+12
For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=10⋅12=120 and whose sum is b=23.
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Factor 23 out of 23k.
10k2+23(k)+12
Rewrite 23 as 8 plus 15
10k2+(8+15)k+12
Apply the distributive property.
10k2+8k+15k+12
10k2+8k+15k+12
Factor out the greatest common factor from each group.
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Group the first two terms and the last two terms.
(10k2+8k)+15k+12
Factor out the greatest common factor (GCF) from each group.
2k(5k+4)+3(5k+4)
2k(5k+4)+3(5k+4)
Factor the polynomial by factoring out the greatest common factor, 5k+4.
(5k+4)(2k+3)
Factor 10k^2+23k+12

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