Factor 27h^3+64

Math
27h3+64
Rewrite 27h3 as (3h)3.
(3h)3+64
Rewrite 64 as 43.
(3h)3+43
Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2-ab+b2) where a=3h and b=4.
(3h+4)((3h)2-(3h)⋅4+42)
Simplify.
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Apply the product rule to 3h.
(3h+4)(32h2-(3h)⋅4+42)
Raise 3 to the power of 2.
(3h+4)(9h2-(3h)⋅4+42)
Multiply 3 by -1.
(3h+4)(9h2-3h⋅4+42)
Multiply 4 by -3.
(3h+4)(9h2-12h+42)
Raise 4 to the power of 2.
(3h+4)(9h2-12h+16)
(3h+4)(9h2-12h+16)
Factor 27h^3+64

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