Factor 64a^3+b^3

Math
64a3+b3
Rewrite 64a3 as (4a)3.
(4a)3+b3
Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2-ab+b2) where a=4a and b=b.
(4a+b)((4a)2-(4a)b+b2)
Simplify.
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Apply the product rule to 4a.
(4a+b)(42a2-(4a)b+b2)
Raise 4 to the power of 2.
(4a+b)(16a2-(4a)b+b2)
Multiply 4 by -1.
(4a+b)(16a2-4ab+b2)
(4a+b)(16a2-4ab+b2)
Factor 64a^3+b^3

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