Factor (a+3b)^2-25

${(a + 3 b)}^{2} - 25$

Rewrite $25$ as $5^{2}$ .

${(a + 3 b)}^{2} - 5^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = a + 3 b$ and $b = 5$ .

$(a + 3 b + 5) (a + 3 b - 5)$

Factor (a+3b)^2-25

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