# Find the Surface Area pyramid (6km)(6km)(8km) h=6kml=8kmw=6km
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area lw, and sl and sw represent the slant height on the length and slant height on the width.
(length)⋅(width)+(width)⋅sl+(length)⋅sw
Substitute the values of the length l=8, the width w=6, and the height h=6 into the formula for surface area of a pyramid.
8⋅6+6⋅(82)2+(6)2+8⋅(62)2+(6)2
Simplify each term.
Multiply 8 by 6.
48+6⋅(82)2+(6)2+8⋅(62)2+(6)2
Divide 8 by 2.
48+6⋅42+(6)2+8⋅(62)2+(6)2
Raise 4 to the power of 2.
48+6⋅16+(6)2+8⋅(62)2+(6)2
Raise 6 to the power of 2.
48+6⋅16+36+8⋅(62)2+(6)2
Add 16 and 36.
48+6⋅52+8⋅(62)2+(6)2
Rewrite 52 as 22⋅13.
Factor 4 out of 52.
48+6⋅4(13)+8⋅(62)2+(6)2
Rewrite 4 as 22.
48+6⋅22⋅13+8⋅(62)2+(6)2
48+6⋅22⋅13+8⋅(62)2+(6)2
Pull terms out from under the radical.
48+6⋅(213)+8⋅(62)2+(6)2
Multiply 2 by 6.
48+1213+8⋅(62)2+(6)2
Divide 6 by 2.
48+1213+8⋅32+(6)2
Raise 3 to the power of 2.
48+1213+8⋅9+(6)2
Raise 6 to the power of 2.
48+1213+8⋅9+36
Add 9 and 36.
48+1213+8⋅45
Rewrite 45 as 32⋅5.
Factor 9 out of 45.
48+1213+8⋅9(5)
Rewrite 9 as 32.
48+1213+8⋅32⋅5
48+1213+8⋅32⋅5
Pull terms out from under the radical.
48+1213+8⋅(35)
Multiply 3 by 8.
48+1213+245
48+1213+245
Calculate the approximate solution to 4 decimal places.
144.9322(km)2
Find the Surface Area pyramid (6km)(6km)(8km)

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