Solve for b -1+2b=2-3b+2b

$- 1 + 2 b = 2 - 3 b + 2 b$

Since $b$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 - 3 b + 2 b = - 1 + 2 b$

Add $- 3 b$ and $2 b$ .

$2 - b = - 1 + 2 b$

Move all terms containing $b$ to the left side of the equation.

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Subtract $2 b$ from both sides of the equation.

$2 - b - 2 b = - 1$

Subtract $2 b$ from $- b$ .

$2 - 3 b = - 1$

Move all terms not containing $b$ to the right side of the equation.

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Subtract $2$ from both sides of the equation.

$- 3 b = - 1 - 2$

Subtract $2$ from $- 1$ .

$- 3 b = - 3$

Divide each term by $- 3$ and simplify.

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Divide each term in $- 3 b = - 3$ by $- 3$ .

$\frac{- 3 b}{- 3} = \frac{- 3}{- 3}$

Cancel the common factor of $- 3$ .

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Cancel the common factor.

$\frac{- 3 b}{- 3} = \frac{- 3}{- 3}$

Divide $b$ by $1$ .

$b = \frac{- 3}{- 3}$

Divide $- 3$ by $- 3$ .

$b = 1$

Solve for b -1+2b=2-3b+2b

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