Solve for b 2/5b+4/5=-6/5

$\frac{2}{5} b + \frac{4}{5} = - \frac{6}{5}$

Combine $\frac{2}{5}$ and $b$ .

$\frac{2 b}{5} + \frac{4}{5} = - \frac{6}{5}$

Move all terms not containing $b$ to the right side of the equation.

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Subtract $\frac{4}{5}$ from both sides of the equation.

$\frac{2 b}{5} = - \frac{6}{5} - \frac{4}{5}$

Combine the numerators over the common denominator.

$\frac{2 b}{5} = \frac{- 6 - 4}{5}$

Subtract $4$ from $- 6$ .

$\frac{2 b}{5} = \frac{- 10}{5}$

Divide $- 10$ by $5$ .

$\frac{2 b}{5} = - 2$

Multiply both sides of the equation by $\frac{5}{2}$ .

$\frac{5}{2} \cdot \frac{2 b}{5} = \frac{5}{2} \cdot - 2$

Simplify both sides of the equation.

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Simplify $\frac{5}{2} \cdot \frac{2 b}{5}$ .

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Cancel the common factor of $5$ .

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Cancel the common factor.

$\frac{5}{2} \cdot \frac{2 b}{5} = \frac{5}{2} \cdot - 2$

Rewrite the expression.

$\frac{1}{2} \cdot (2 b) = \frac{5}{2} \cdot - 2$

Cancel the common factor of $2$ .

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Factor $2$ out of $2 b$ .

$\frac{1}{2} \cdot (2 (b)) = \frac{5}{2} \cdot - 2$

Cancel the common factor.

$\frac{1}{2} \cdot (2 b) = \frac{5}{2} \cdot - 2$

Rewrite the expression.

$b = \frac{5}{2} \cdot - 2$

Simplify $\frac{5}{2} \cdot - 2$ .

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Cancel the common factor of $2$ .

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Factor $2$ out of $- 2$ .

$b = \frac{5}{2} \cdot (2 (- 1))$

Cancel the common factor.

$b = \frac{5}{2} \cdot (2 \cdot - 1)$

Rewrite the expression.

$b = 5 \cdot - 1$

Multiply $5$ by $- 1$ .

$b = - 5$

Solve for b 2/5b+4/5=-6/5

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