Solve for b abcd+dcba=5555

$a b c d + d c b a = 5555$

Add $a b c d$ and $d c b a$ .

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Reorder $b$ and $a$ .

$a b c d + a b c d = 5555$

Add $a b c d$ and $a b c d$ .

$2 a b c d = 5555$

Divide each term by $2 a c d$ and simplify.

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Divide each term in $2 a b c d = 5555$ by $2 a c d$ .

$\frac{2 a b c d}{2 a c d} = \frac{5555}{2 a c d}$

Simplify $\frac{2 a b c d}{2 a c d}$ .

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Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 a b c d}{2 a c d} = \frac{5555}{2 a c d}$

Rewrite the expression.

$\frac{a b c d}{a c d} = \frac{5555}{2 a c d}$

Cancel the common factor of $a$ .

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Cancel the common factor.

$\frac{a b c d}{a c d} = \frac{5555}{2 a c d}$

Rewrite the expression.

$\frac{b c d}{c d} = \frac{5555}{2 a c d}$

Cancel the common factor of $c$ .

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Cancel the common factor.

$\frac{b c d}{c d} = \frac{5555}{2 a c d}$

Rewrite the expression.

$\frac{b d}{d} = \frac{5555}{2 a c d}$

Cancel the common factor of $d$ .

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Cancel the common factor.

$\frac{b d}{d} = \frac{5555}{2 a c d}$

Divide $b$ by $1$ .

$b = \frac{5555}{2 a c d}$

Solve for b abcd+dcba=5555

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