Solve for c (2c-1)/4+1=(3c+2)/3

$\frac{2 c - 1}{4} + 1 = \frac{3 c + 2}{3}$

Move $\frac{3 c + 2}{3}$ to the left side of the equation by subtracting it from both sides.

$\frac{2 c - 1}{4} + 1 - \frac{3 c + 2}{3} = 0$

Simplify $\frac{2 c - 1}{4} + 1 - \frac{3 c + 2}{3}$ .

Tap for more steps…

Write $1$ as a fraction with a common denominator.

$\frac{2 c - 1}{4} + \frac{4}{4} - \frac{3 c + 2}{3} = 0$

Combine the numerators over the common denominator.

$\frac{2 c - 1 + 4}{4} - \frac{3 c + 2}{3} = 0$

Add $- 1$ and $4$ .

$\frac{2 c + 3}{4} - \frac{3 c + 2}{3} = 0$

To write $\frac{2 c + 3}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{2 c + 3}{4} \cdot \frac{3}{3} - \frac{3 c + 2}{3} = 0$

To write $- \frac{3 c + 2}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{2 c + 3}{4} \cdot \frac{3}{3} - \frac{3 c + 2}{3} \cdot \frac{4}{4} = 0$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

Tap for more steps…

Multiply $\frac{2 c + 3}{4}$ and $\frac{3}{3}$ .

$\frac{(2 c + 3) \cdot 3}{4 \cdot 3} - \frac{3 c + 2}{3} \cdot \frac{4}{4} = 0$

Multiply $4$ by $3$ .

$\frac{(2 c + 3) \cdot 3}{12} - \frac{3 c + 2}{3} \cdot \frac{4}{4} = 0$

Multiply $\frac{3 c + 2}{3}$ and $\frac{4}{4}$ .

$\frac{(2 c + 3) \cdot 3}{12} - \frac{(3 c + 2) \cdot 4}{3 \cdot 4} = 0$

Multiply $3$ by $4$ .

$\frac{(2 c + 3) \cdot 3}{12} - \frac{(3 c + 2) \cdot 4}{12} = 0$

Combine the numerators over the common denominator.

$\frac{(2 c + 3) \cdot 3 - (3 c + 2) \cdot 4}{12} = 0$

Simplify the numerator.

Tap for more steps…

Apply the distributive property.

$\frac{2 c \cdot 3 + 3 \cdot 3 - (3 c + 2) \cdot 4}{12} = 0$

Multiply $3$ by $2$ .

$\frac{6 c + 3 \cdot 3 - (3 c + 2) \cdot 4}{12} = 0$

Multiply $3$ by $3$ .

$\frac{6 c + 9 - (3 c + 2) \cdot 4}{12} = 0$

Apply the distributive property.

$\frac{6 c + 9 + (- (3 c) - 1 \cdot 2) \cdot 4}{12} = 0$

Multiply $3$ by $- 1$ .

$\frac{6 c + 9 + (- 3 c - 1 \cdot 2) \cdot 4}{12} = 0$

Multiply $- 1$ by $2$ .

$\frac{6 c + 9 + (- 3 c - 2) \cdot 4}{12} = 0$

Apply the distributive property.

$\frac{6 c + 9 - 3 c \cdot 4 - 2 \cdot 4}{12} = 0$

Multiply $4$ by $- 3$ .

$\frac{6 c + 9 - 12 c - 2 \cdot 4}{12} = 0$

Multiply $- 2$ by $4$ .

$\frac{6 c + 9 - 12 c - 8}{12} = 0$

Subtract $12 c$ from $6 c$ .

$\frac{- 6 c + 9 - 8}{12} = 0$

Subtract $8$ from $9$ .

$\frac{- 6 c + 1}{12} = 0$

Simplify with factoring out.

Tap for more steps…

Factor $- 1$ out of $- 6 c$ .

$\frac{- (6 c) + 1}{12} = 0$

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- (6 c) - 1 (- 1)}{12} = 0$

Factor $- 1$ out of $- (6 c) - 1 (- 1)$ .

$\frac{- (6 c - 1)}{12} = 0$

Simplify the expression.

Tap for more steps…

Rewrite $- (6 c - 1)$ as $- 1 (6 c - 1)$ .

$\frac{- 1 (6 c - 1)}{12} = 0$

Move the negative in front of the fraction.

$- \frac{6 c - 1}{12} = 0$

Since this is the only denominator in the list, the result is the LCD: $12$ .

$12$

Multiply each term by $12$ and simplify.

Tap for more steps…

Multiply each term in $- \frac{6 c - 1}{12} = 0$ by $12$ .

$(- \frac{6 c - 1}{12}) \cdot 12 = 0 \cdot 12$

Simplify $(- \frac{6 c - 1}{12}) \cdot 12$ .

Tap for more steps…

Cancel the common factor of $12$ .

Tap for more steps…

Move the leading negative in $- \frac{6 c - 1}{12}$ into the numerator.

$\frac{- (6 c - 1)}{12} \cdot 12 = 0 \cdot 12$

Cancel the common factor.

$\frac{- (6 c - 1)}{12} \cdot 12 = 0 \cdot 12$

Rewrite the expression.

$- (6 c - 1) = 0 \cdot 12$

Apply the distributive property.

$- (6 c) - - 1 = 0 \cdot 12$

Multiply.

Tap for more steps…

Multiply $6$ by $- 1$ .

$- 6 c - - 1 = 0 \cdot 12$

Multiply $- 1$ by $- 1$ .

$- 6 c + 1 = 0 \cdot 12$

Multiply $0$ by $12$ .

$- 6 c + 1 = 0$

Subtract $1$ from both sides of the equation.

$- 6 c = - 1$

Divide each term by $- 6$ and simplify.

Tap for more steps…

Divide each term in $- 6 c = - 1$ by $- 6$ .

$\frac{- 6 c}{- 6} = \frac{- 1}{- 6}$

Cancel the common factor of $- 6$ .

Tap for more steps…

Cancel the common factor.

$\frac{- 6 c}{- 6} = \frac{- 1}{- 6}$

Divide $c$ by $1$ .

$c = \frac{- 1}{- 6}$

Dividing two negative values results in a positive value.

$c = \frac{1}{6}$

The result can be shown in multiple forms.

Exact Form:

$c = \frac{1}{6}$

Decimal Form:

$c = 0.1\overline{6}$

Solve for c (2c-1)/4+1=(3c+2)/3

Meet the Team our Math Expers

Our Professionals

Robert Kristofer

Anna Frok

Magnus Flores

Lydia Fran

We are MathExperts

We can solve all your math problems