Solve for c 2c-3(c+4)=-5

$2 c - 3 (c + 4) = - 5$

Simplify $2 c - 3 (c + 4)$ .

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Simplify each term.

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Apply the distributive property.

$2 c - 3 c - 3 \cdot 4 = - 5$

Multiply $- 3$ by $4$ .

$2 c - 3 c - 12 = - 5$

Subtract $3 c$ from $2 c$ .

$- c - 12 = - 5$

Move all terms not containing $c$ to the right side of the equation.

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Add $12$ to both sides of the equation.

$- c = - 5 + 12$

Add $- 5$ and $12$ .

$- c = 7$

Multiply each term in $- c = 7$ by $- 1$

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Multiply each term in $- c = 7$ by $- 1$ .

$(- c) \cdot - 1 = 7 \cdot - 1$

Multiply $(- c) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 c = 7 \cdot - 1$

Multiply $c$ by $1$ .

$c = 7 \cdot - 1$

Multiply $7$ by $- 1$ .

$c = - 7$

Solve for c 2c-3(c+4)=-5

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