Solve for c 2c+5=3c-10

$2 c + 5 = 3 c - 10$

Move all terms containing $c$ to the left side of the equation.

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Subtract $3 c$ from both sides of the equation.

$2 c + 5 - 3 c = - 10$

Subtract $3 c$ from $2 c$ .

$- c + 5 = - 10$

Move all terms not containing $c$ to the right side of the equation.

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Subtract $5$ from both sides of the equation.

$- c = - 10 - 5$

Subtract $5$ from $- 10$ .

$- c = - 15$

Multiply each term in $- c = - 15$ by $- 1$

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Multiply each term in $- c = - 15$ by $- 1$ .

$(- c) \cdot - 1 = (- 15) \cdot - 1$

Multiply $(- c) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 c = (- 15) \cdot - 1$

Multiply $c$ by $1$ .

$c = (- 15) \cdot - 1$

Multiply $- 15$ by $- 1$ .

$c = 15$

Solve for c 2c+5=3c-10

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