Solve for c c^2+2c-2=0

Math
c2+2c-2=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=2, and c=-2 into the quadratic formula and solve for c.
-2±22-4⋅(1⋅-2)2⋅1
Simplify.
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Simplify the numerator.
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Raise 2 to the power of 2.
c=-2±4-4⋅(1⋅-2)2⋅1
Multiply -2 by 1.
c=-2±4-4⋅-22⋅1
Multiply -4 by -2.
c=-2±4+82⋅1
Add 4 and 8.
c=-2±122⋅1
Rewrite 12 as 22⋅3.
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Factor 4 out of 12.
c=-2±4(3)2⋅1
Rewrite 4 as 22.
c=-2±22⋅32⋅1
c=-2±22⋅32⋅1
Pull terms out from under the radical.
c=-2±232⋅1
c=-2±232⋅1
Multiply 2 by 1.
c=-2±232
Simplify -2±232.
c=-1±3
c=-1±3
The final answer is the combination of both solutions.
c=-1+3,-1-3
The result can be shown in multiple forms.
Exact Form:
c=-1+3,-1-3
Decimal Form:
c=0.73205080…,-2.73205080…
Solve for c c^2+2c-2=0

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