Solve for c ( square root of 16.8^2+22.4^2)=c

$(\sqrt{{16.8}^{2} + {22.4}^{2}}) = c$

Rewrite the equation as $c = \sqrt{{16.8}^{2} + {22.4}^{2}}$ .

$c = \sqrt{{16.8}^{2} + {22.4}^{2}}$

Simplify $\sqrt{{16.8}^{2} + {22.4}^{2}}$ .

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Raise $16.8$ to the power of $2$ .

$c = \sqrt{282.24 + {22.4}^{2}}$

Raise $22.4$ to the power of $2$ .

$c = \sqrt{282.24 + 501.76}$

Add $282.24$ and $501.76$ .

$c = \sqrt{784}$

Rewrite $784$ as $28^{2}$ .

$c = \sqrt{28^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$c = 28$

Solve for c ( square root of 16.8^2+22.4^2)=c

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