Solve for d 4d-3-2d=-15

$4 d - 3 - 2 d = - 15$

Subtract $2 d$ from $4 d$ .

$2 d - 3 = - 15$

Move all terms not containing $d$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$2 d = - 15 + 3$

Add $- 15$ and $3$ .

$2 d = - 12$

Divide each term by $2$ and simplify.

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Divide each term in $2 d = - 12$ by $2$ .

$\frac{2 d}{2} = \frac{- 12}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 d}{2} = \frac{- 12}{2}$

Divide $d$ by $1$ .

$d = \frac{- 12}{2}$

Divide $- 12$ by $2$ .

$d = - 6$

Solve for d 4d-3-2d=-15

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