Solve for d 4*(d-3)=9

$4 \cdot (d - 3) = 9$

Divide each term by $4$ and simplify.

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Divide each term in $4 \cdot (d - 3) = 9$ by $4$ .

$\frac{4 \cdot (d - 3)}{4} = \frac{9}{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 \cdot (d - 3)}{4} = \frac{9}{4}$

Divide $d - 3$ by $1$ .

$d - 3 = \frac{9}{4}$

Move all terms not containing $d$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$d = \frac{9}{4} + 3$

To write $3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$d = \frac{9}{4} + 3 \cdot \frac{4}{4}$

Combine $3$ and $\frac{4}{4}$ .

$d = \frac{9}{4} + \frac{3 \cdot 4}{4}$

Combine the numerators over the common denominator.

$d = \frac{9 + 3 \cdot 4}{4}$

Simplify the numerator.

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Multiply $3$ by $4$ .

$d = \frac{9 + 12}{4}$

Add $9$ and $12$ .

$d = \frac{21}{4}$

The result can be shown in multiple forms.

Exact Form:

$d = \frac{21}{4}$

Decimal Form:

$d = 5.25$

Mixed Number Form:

$d = 5 \frac{1}{4}$

Solve for d 4*(d-3)=9

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