Solve for h 104=1/2*(h(10+3))

$104 = \frac{1}{2} \cdot (h (10 + 3))$

Rewrite the equation as $\frac{1}{2} \cdot (h (10 + 3)) = 104$ .

$\frac{1}{2} \cdot (h (10 + 3)) = 104$

Multiply both sides of the equation by $\frac{1}{\frac{1}{2} \cdot (10 + 3)}$ .

$\frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Simplify both sides of the equation.

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Simplify $\frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot \frac{1}{2} \cdot (h (10 + 3))$ .

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Add $10$ and $3$ .

$\frac{1}{\frac{1}{2} \cdot 13} \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Combine $\frac{1}{2}$ and $13$ .

$\frac{1}{\frac{13}{2}} \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Multiply the numerator by the reciprocal of the denominator.

$1 (\frac{2}{13}) \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Multiply $\frac{2}{13}$ by $1$ .

$\frac{2}{13} \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2}{13} \cdot \frac{1}{2} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Rewrite the expression.

$\frac{1}{13} \cdot (h (10 + 3)) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Add $10$ and $3$ .

$\frac{1}{13} \cdot (h \cdot 13) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Cancel the common factor of $13$ .

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Factor $13$ out of $h \cdot 13$ .

$\frac{1}{13} \cdot (13 \cdot h) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Cancel the common factor.

$\frac{1}{13} \cdot (13 \cdot h) = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Rewrite the expression.

$h = \frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$

Simplify $\frac{1}{\frac{1}{2} \cdot (10 + 3)} \cdot 104$ .

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Add $10$ and $3$ .

$h = \frac{1}{\frac{1}{2} \cdot 13} \cdot 104$

Combine $\frac{1}{2}$ and $13$ .

$h = \frac{1}{\frac{13}{2}} \cdot 104$

Multiply the numerator by the reciprocal of the denominator.

$h = 1 (\frac{2}{13}) \cdot 104$

Multiply $\frac{2}{13}$ by $1$ .

$h = \frac{2}{13} \cdot 104$

Cancel the common factor of $13$ .

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Factor $13$ out of $104$ .

$h = \frac{2}{13} \cdot (13 (8))$

Cancel the common factor.

$h = \frac{2}{13} \cdot (13 \cdot 8)$

Rewrite the expression.

$h = 2 \cdot 8$

Multiply $2$ by $8$ .

$h = 16$

Solve for h 104=1/2*(h(10+3))

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