Solve for h 7=(16/81)*(9)^2*h

$7 = (\frac{16}{81}) \cdot {(9)}^{2} \cdot h$

Rewrite the equation as $(\frac{16}{81}) \cdot {(9)}^{2} \cdot h = 7$ .

$(\frac{16}{81}) \cdot {(9)}^{2} \cdot h = 7$

Simplify.

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Raise $9$ to the power of $2$ .

$\frac{16}{81} \cdot 81 \cdot h = 7$

Cancel the common factor of $81$ .

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Cancel the common factor.

$\frac{16}{81} \cdot 81 \cdot h = 7$

Rewrite the expression.

$16 \cdot h = 7$

Divide each term by $16$ and simplify.

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Divide each term in $16 \cdot h = 7$ by $16$ .

$\frac{16 \cdot h}{16} = \frac{7}{16}$

Cancel the common factor of $16$ .

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Cancel the common factor.

$\frac{16 \cdot h}{16} = \frac{7}{16}$

Divide $h$ by $1$ .

$h = \frac{7}{16}$

The result can be shown in multiple forms.

Exact Form:

$h = \frac{7}{16}$

Decimal Form:

$h = 0.4375$

Solve for h 7=(16/81)*(9)^2*h

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