Solve for n 20(n+6)=4(30+5n)

$20 (n + 6) = 4 (30 + 5 n)$

Simplify $20 (n + 6)$ .

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Apply the distributive property.

$20 n + 20 \cdot 6 = 4 (30 + 5 n)$

Multiply $20$ by $6$ .

$20 n + 120 = 4 (30 + 5 n)$

Simplify $4 (30 + 5 n)$ .

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Apply the distributive property.

$20 n + 120 = 4 \cdot 30 + 4 (5 n)$

Multiply.

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Multiply $4$ by $30$ .

$20 n + 120 = 120 + 4 (5 n)$

Multiply $5$ by $4$ .

$20 n + 120 = 120 + 20 n$

Move all terms containing $n$ to the left side of the equation.

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Subtract $20 n$ from both sides of the equation.

$20 n + 120 - 20 n = 120$

Combine the opposite terms in $20 n + 120 - 20 n$ .

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Subtract $20 n$ from $20 n$ .

$0 + 120 = 120$

Add $0$ and $120$ .

$120 = 120$

Since $120 = 120$ , the equation will always be true for any value of $n$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$

Solve for n 20(n+6)=4(30+5n)

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