Solve for p p-4/n=pn

$p - \frac{4}{n} = p n$

Subtract $p n$ from both sides of the equation.

$p - \frac{4}{n} - p n = 0$

Add $\frac{4}{n}$ to both sides of the equation.

$p - p n = \frac{4}{n}$

Factor $p$ out of $p - p n$ .

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Factor $p$ out of $p^{1}$ .

$p \cdot 1 - p n = \frac{4}{n}$

Factor $p$ out of $- p n$ .

$p \cdot 1 + p (- 1 n) = \frac{4}{n}$

Factor $p$ out of $p \cdot 1 + p (- 1 n)$ .

$p (1 - 1 n) = \frac{4}{n}$

Rewrite $- 1 n$ as $- n$ .

$p (1 - n) = \frac{4}{n}$

Divide each term by $1 - n$ and simplify.

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Divide each term in $p (1 - n) = \frac{4}{n}$ by $1 - n$ .

$\frac{p (1 - n)}{1 - n} = \frac{4}{n} \cdot \frac{1}{1 - n}$

Cancel the common factor of $1 - n$ .

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Cancel the common factor.

$\frac{p (1 - n)}{1 - n} = \frac{4}{n} \cdot \frac{1}{1 - n}$

Divide $p$ by $1$ .

$p = \frac{4}{n} \cdot \frac{1}{1 - n}$

Multiply $\frac{4}{n}$ and $\frac{1}{1 - n}$ .

$p = \frac{4}{n (1 - n)}$

Solve for p p-4/n=pn

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