Solve for r -6r+2(r+2)-5=-20

$- 6 r + 2 (r + 2) - 5 = - 20$

Simplify $- 6 r + 2 (r + 2) - 5$ .

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Simplify each term.

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Apply the distributive property.

$- 6 r + 2 r + 2 \cdot 2 - 5 = - 20$

Multiply $2$ by $2$ .

$- 6 r + 2 r + 4 - 5 = - 20$

Simplify by adding terms.

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Add $- 6 r$ and $2 r$ .

$- 4 r + 4 - 5 = - 20$

Subtract $5$ from $4$ .

$- 4 r - 1 = - 20$

Move all terms not containing $r$ to the right side of the equation.

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Add $1$ to both sides of the equation.

$- 4 r = - 20 + 1$

Add $- 20$ and $1$ .

$- 4 r = - 19$

Divide each term by $- 4$ and simplify.

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Divide each term in $- 4 r = - 19$ by $- 4$ .

$\frac{- 4 r}{- 4} = \frac{- 19}{- 4}$

Cancel the common factor of $- 4$ .

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Cancel the common factor.

$\frac{- 4 r}{- 4} = \frac{- 19}{- 4}$

Divide $r$ by $1$ .

$r = \frac{- 19}{- 4}$

Dividing two negative values results in a positive value.

$r = \frac{19}{4}$

The result can be shown in multiple forms.

Exact Form:

$r = \frac{19}{4}$

Decimal Form:

$r = 4.75$

Mixed Number Form:

$r = 4 \frac{3}{4}$

Solve for r -6r+2(r+2)-5=-20

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