Solve for t (11+9)(2t-6)=0

$(11 + 9) (2 t - 6) = 0$

Add $11$ and $9$ .

$20 (2 t - 6) = 0$

Divide each term by $20$ and simplify.

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Divide each term in $20 (2 t - 6) = 0$ by $20$ .

$\frac{20 (2 t - 6)}{20} = \frac{0}{20}$

Cancel the common factor of $20$ .

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Cancel the common factor.

$\frac{20 (2 t - 6)}{20} = \frac{0}{20}$

Divide $2 t - 6$ by $1$ .

$2 t - 6 = \frac{0}{20}$

Divide $0$ by $20$ .

$2 t - 6 = 0$

Add $6$ to both sides of the equation.

$2 t = 6$

Divide each term by $2$ and simplify.

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Divide each term in $2 t = 6$ by $2$ .

$\frac{2 t}{2} = \frac{6}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 t}{2} = \frac{6}{2}$

Divide $t$ by $1$ .

$t = \frac{6}{2}$

Divide $6$ by $2$ .

$t = 3$

Solve for t (11+9)(2t-6)=0

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