Solve for t t^2-9t-7=0

Math
t2-9t-7=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=-9, and c=-7 into the quadratic formula and solve for t.
9±(-9)2-4⋅(1⋅-7)2⋅1
Simplify.
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Simplify the numerator.
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Raise -9 to the power of 2.
t=9±81-4⋅(1⋅-7)2⋅1
Multiply -7 by 1.
t=9±81-4⋅-72⋅1
Multiply -4 by -7.
t=9±81+282⋅1
Add 81 and 28.
t=9±1092⋅1
t=9±1092⋅1
Multiply 2 by 1.
t=9±1092
t=9±1092
The final answer is the combination of both solutions.
t=9+1092,9-1092
The result can be shown in multiple forms.
Exact Form:
t=9+1092,9-1092
Decimal Form:
t=9.72015325…,-0.72015325…
Solve for t t^2-9t-7=0

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