Solve for u d=ut+kt^2

$d = u t + k t^{2}$

Rewrite the equation as $u t + k t^{2} = d$ .

$u t + k t^{2} = d$

Subtract $k t^{2}$ from both sides of the equation.

$u t = d - k t^{2}$

Divide each term by $t$ and simplify.

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Divide each term in $u t = d - k t^{2}$ by $t$ .

$\frac{u t}{t} = \frac{d}{t} + \frac{- k t^{2}}{t}$

Cancel the common factor of $t$ .

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Cancel the common factor.

$\frac{u t}{t} = \frac{d}{t} + \frac{- k t^{2}}{t}$

Divide $u$ by $1$ .

$u = \frac{d}{t} + \frac{- k t^{2}}{t}$

Cancel the common factor of $t^{2}$ and $t$ .

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Factor $t$ out of $- k t^{2}$ .

$u = \frac{d}{t} + \frac{t (- k t)}{t}$

Cancel the common factors.

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Raise $t$ to the power of $1$ .

$u = \frac{d}{t} + \frac{t (- k t)}{t^{1}}$

Factor $t$ out of $t^{1}$ .

$u = \frac{d}{t} + \frac{t (- k t)}{t \cdot 1}$

Cancel the common factor.

$u = \frac{d}{t} + \frac{t (- k t)}{t \cdot 1}$

Rewrite the expression.

$u = \frac{d}{t} + \frac{- k t}{1}$

Divide $- k t$ by $1$ .

$u = \frac{d}{t} - k t$

Solve for u d=ut+kt^2

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