Solve for v 2v^2-16v+15=(v-6)^2

Math
2v2-16v+15=(v-6)2
Simplify (v-6)2.
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Rewrite (v-6)2 as (v-6)(v-6).
2v2-16v+15=(v-6)(v-6)
Expand (v-6)(v-6) using the FOIL Method.
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Apply the distributive property.
2v2-16v+15=v(v-6)-6(v-6)
Apply the distributive property.
2v2-16v+15=v⋅v+v⋅-6-6(v-6)
Apply the distributive property.
2v2-16v+15=v⋅v+v⋅-6-6v-6⋅-6
2v2-16v+15=v⋅v+v⋅-6-6v-6⋅-6
Simplify and combine like terms.
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Simplify each term.
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Multiply v by v.
2v2-16v+15=v2+v⋅-6-6v-6⋅-6
Move -6 to the left of v.
2v2-16v+15=v2-6⋅v-6v-6⋅-6
Multiply -6 by -6.
2v2-16v+15=v2-6v-6v+36
2v2-16v+15=v2-6v-6v+36
Subtract 6v from -6v.
2v2-16v+15=v2-12v+36
2v2-16v+15=v2-12v+36
2v2-16v+15=v2-12v+36
Move all terms containing v to the left side of the equation.
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Subtract v2 from both sides of the equation.
2v2-16v+15-v2=-12v+36
Add 12v to both sides of the equation.
2v2-16v+15-v2+12v=36
Subtract v2 from 2v2.
v2-16v+15+12v=36
Add -16v and 12v.
v2-4v+15=36
v2-4v+15=36
Move 36 to the left side of the equation by subtracting it from both sides.
v2-4v+15-36=0
Subtract 36 from 15.
v2-4v-21=0
Factor v2-4v-21 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -21 and whose sum is -4.
-7,3
Write the factored form using these integers.
(v-7)(v+3)=0
(v-7)(v+3)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
v-7=0
v+3=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
v-7=0
Add 7 to both sides of the equation.
v=7
v=7
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
v+3=0
Subtract 3 from both sides of the equation.
v=-3
v=-3
The final solution is all the values that make (v-7)(v+3)=0 true.
v=7,-3
Solve for v 2v^2-16v+15=(v-6)^2

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