Solve for v v^2+16=8v

Math
v2+16=8v
Subtract 8v from both sides of the equation.
v2+16-8v=0
Factor using the perfect square rule.
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Rearrange terms.
v2-8v+16=0
Rewrite 16 as 42.
v2-8v+42=0
Check the middle term by multiplying 2ab and compare this result with the middle term in the original expression.
2ab=2⋅v⋅-4
Simplify.
2ab=-8v
Factor using the perfect square trinomial rule a2-2ab+b2=(a-b)2, where a=v and b=-4.
(v-4)2=0
(v-4)2=0
Set the v-4 equal to 0.
v-4=0
Add 4 to both sides of the equation.
v=4
Solve for v v^2+16=8v

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