v2+32=12v

Subtract 12v from both sides of the equation.

v2+32-12v=0

Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 32 and whose sum is -12.

-8,-4

Write the factored form using these integers.

(v-8)(v-4)=0

(v-8)(v-4)=0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

v-8=0

v-4=0

Set the first factor equal to 0.

v-8=0

Add 8 to both sides of the equation.

v=8

v=8

Set the next factor equal to 0.

v-4=0

Add 4 to both sides of the equation.

v=4

v=4

The final solution is all the values that make (v-8)(v-4)=0 true.

v=8,4

Solve for v v^2+32=12v