Solve for v v^2+32=12v

Math
v2+32=12v
Subtract 12v from both sides of the equation.
v2+32-12v=0
Factor v2+32-12v using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 32 and whose sum is -12.
-8,-4
Write the factored form using these integers.
(v-8)(v-4)=0
(v-8)(v-4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
v-8=0
v-4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
v-8=0
Add 8 to both sides of the equation.
v=8
v=8
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
v-4=0
Add 4 to both sides of the equation.
v=4
v=4
The final solution is all the values that make (v-8)(v-4)=0 true.
v=8,4
Solve for v v^2+32=12v

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