Solve for w w^2-5w-6=0

Math
w2-5w-6=0
Factor w2-5w-6 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -6 and whose sum is -5.
-6,1
Write the factored form using these integers.
(w-6)(w+1)=0
(w-6)(w+1)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
w-6=0
w+1=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
w-6=0
Add 6 to both sides of the equation.
w=6
w=6
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
w+1=0
Subtract 1 from both sides of the equation.
w=-1
w=-1
The final solution is all the values that make (w-6)(w+1)=0 true.
w=6,-1
Solve for w w^2-5w-6=0

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