Solve for x 14(2x-3)-5(x+4)=2(3x+5)+5x

$14 (2 x - 3) - 5 (x + 4) = 2 (3 x + 5) + 5 x$

Simplify $14 (2 x - 3) - 5 (x + 4)$ .

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Simplify each term.

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Apply the distributive property.

$14 (2 x) + 14 \cdot - 3 - 5 (x + 4) = 2 (3 x + 5) + 5 x$

Multiply $2$ by $14$ .

$28 x + 14 \cdot - 3 - 5 (x + 4) = 2 (3 x + 5) + 5 x$

Multiply $14$ by $- 3$ .

$28 x - 42 - 5 (x + 4) = 2 (3 x + 5) + 5 x$

Apply the distributive property.

$28 x - 42 - 5 x - 5 \cdot 4 = 2 (3 x + 5) + 5 x$

Multiply $- 5$ by $4$ .

$28 x - 42 - 5 x - 20 = 2 (3 x + 5) + 5 x$

Simplify by adding terms.

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Subtract $5 x$ from $28 x$ .

$23 x - 42 - 20 = 2 (3 x + 5) + 5 x$

Subtract $20$ from $- 42$ .

$23 x - 62 = 2 (3 x + 5) + 5 x$

Simplify $2 (3 x + 5) + 5 x$ .

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Simplify each term.

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Apply the distributive property.

$23 x - 62 = 2 (3 x) + 2 \cdot 5 + 5 x$

Multiply $3$ by $2$ .

$23 x - 62 = 6 x + 2 \cdot 5 + 5 x$

Multiply $2$ by $5$ .

$23 x - 62 = 6 x + 10 + 5 x$

Add $6 x$ and $5 x$ .

$23 x - 62 = 11 x + 10$

Move all terms containing $x$ to the left side of the equation.

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Subtract $11 x$ from both sides of the equation.

$23 x - 62 - 11 x = 10$

Subtract $11 x$ from $23 x$ .

$12 x - 62 = 10$

Move all terms not containing $x$ to the right side of the equation.

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Add $62$ to both sides of the equation.

$12 x = 10 + 62$

Add $10$ and $62$ .

$12 x = 72$

Divide each term by $12$ and simplify.

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Divide each term in $12 x = 72$ by $12$ .

$\frac{12 x}{12} = \frac{72}{12}$

Cancel the common factor of $12$ .

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Cancel the common factor.

$\frac{12 x}{12} = \frac{72}{12}$

Divide $x$ by $1$ .

$x = \frac{72}{12}$

Divide $72$ by $12$ .

$x = 6$

Solve for x 14(2x-3)-5(x+4)=2(3x+5)+5x

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