Solve for y 2x+3y+z=11

$2 x + 3 y + z = 11$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $2 x$ from both sides of the equation.

$3 y + z = 11 - 2 x$

Subtract $z$ from both sides of the equation.

$3 y = 11 - 2 x - z$

Divide each term by $3$ and simplify.

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Divide each term in $3 y = 11 - 2 x - z$ by $3$ .

$\frac{3 y}{3} = \frac{11}{3} + \frac{- 2 x}{3} + \frac{- z}{3}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 y}{3} = \frac{11}{3} + \frac{- 2 x}{3} + \frac{- z}{3}$

Divide $y$ by $1$ .

$y = \frac{11}{3} + \frac{- 2 x}{3} + \frac{- z}{3}$

Simplify each term.

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Move the negative in front of the fraction.

$y = \frac{11}{3} - \frac{(2) x}{3} + \frac{- z}{3}$

Move the negative in front of the fraction.

$y = \frac{11}{3} - \frac{2 x}{3} - \frac{z}{3}$

Solve for y 2x+3y+z=11

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