Solve for y (2y)/9-4=2/3

$\frac{2 y}{9} - 4 = \frac{2}{3}$

Move all terms not containing $y$ to the right side of the equation.

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Add $4$ to both sides of the equation.

$\frac{2 y}{9} = \frac{2}{3} + 4$

To write $4$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{2 y}{9} = \frac{2}{3} + 4 \cdot \frac{3}{3}$

Combine $4$ and $\frac{3}{3}$ .

$\frac{2 y}{9} = \frac{2}{3} + \frac{4 \cdot 3}{3}$

Combine the numerators over the common denominator.

$\frac{2 y}{9} = \frac{2 + 4 \cdot 3}{3}$

Simplify the numerator.

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Multiply $4$ by $3$ .

$\frac{2 y}{9} = \frac{2 + 12}{3}$

Add $2$ and $12$ .

$\frac{2 y}{9} = \frac{14}{3}$

Multiply both sides of the equation by $\frac{9}{2}$ .

$\frac{9}{2} \cdot \frac{2 y}{9} = \frac{9}{2} \cdot \frac{14}{3}$

Simplify both sides of the equation.

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Simplify $\frac{9}{2} \cdot \frac{2 y}{9}$ .

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Cancel the common factor of $9$ .

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Cancel the common factor.

$\frac{9}{2} \cdot \frac{2 y}{9} = \frac{9}{2} \cdot \frac{14}{3}$

Rewrite the expression.

$\frac{1}{2} \cdot (2 y) = \frac{9}{2} \cdot \frac{14}{3}$

Cancel the common factor of $2$ .

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Factor $2$ out of $2 y$ .

$\frac{1}{2} \cdot (2 (y)) = \frac{9}{2} \cdot \frac{14}{3}$

Cancel the common factor.

$\frac{1}{2} \cdot (2 y) = \frac{9}{2} \cdot \frac{14}{3}$

Rewrite the expression.

$y = \frac{9}{2} \cdot \frac{14}{3}$

Simplify $\frac{9}{2} \cdot \frac{14}{3}$ .

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Cancel the common factor of $3$ .

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Factor $3$ out of $9$ .

$y = \frac{3 (3)}{2} \cdot \frac{14}{3}$

Cancel the common factor.

$y = \frac{3 \cdot 3}{2} \cdot \frac{14}{3}$

Rewrite the expression.

$y = \frac{3}{2} \cdot 14$

Cancel the common factor of $2$ .

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Factor $2$ out of $14$ .

$y = \frac{3}{2} \cdot (2 (7))$

Cancel the common factor.

$y = \frac{3}{2} \cdot (2 \cdot 7)$

Rewrite the expression.

$y = 3 \cdot 7$

Multiply $3$ by $7$ .

$y = 21$

Solve for y (2y)/9-4=2/3

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