# Solve for y (2y+4)^2=36 (2y+4)2=36
Take the square root of each side of the equation to set up the solution for y
(2y+4)2⋅12=±36
Remove the perfect root factor 2y+4 under the radical to solve for y.
2y+4=±36
Simplify the right side of the equation.
Rewrite 36 as 62.
2y+4=±62
Pull terms out from under the radical, assuming positive real numbers.
2y+4=±6
2y+4=±6
The complete solution is the result of both the positive and negative portions of the solution.
First, use the positive value of the ± to find the first solution.
2y+4=6
Move all terms not containing y to the right side of the equation.
Subtract 4 from both sides of the equation.
2y=6-4
Subtract 4 from 6.
2y=2
2y=2
Divide each term by 2 and simplify.
Divide each term in 2y=2 by 2.
2y2=22
Cancel the common factor of 2.
Cancel the common factor.
2y2=22
Divide y by 1.
y=22
y=22
Divide 2 by 2.
y=1
y=1
Next, use the negative value of the ± to find the second solution.
2y+4=-6
Move all terms not containing y to the right side of the equation.
Subtract 4 from both sides of the equation.
2y=-6-4
Subtract 4 from -6.
2y=-10
2y=-10
Divide each term by 2 and simplify.
Divide each term in 2y=-10 by 2.
2y2=-102
Cancel the common factor of 2.
Cancel the common factor.
2y2=-102
Divide y by 1.
y=-102
y=-102
Divide -10 by 2.
y=-5
y=-5
The complete solution is the result of both the positive and negative portions of the solution.
y=1,-5
y=1,-5
Solve for y (2y+4)^2=36

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