Solve for y 3c+7y=12

$3 c + 7 y = 12$

Subtract $3 c$ from both sides of the equation.

$7 y = 12 - 3 c$

Divide each term by $7$ and simplify.

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Divide each term in $7 y = 12 - 3 c$ by $7$ .

$\frac{7 y}{7} = \frac{12}{7} + \frac{- 3 c}{7}$

Cancel the common factor of $7$ .

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Cancel the common factor.

$\frac{7 y}{7} = \frac{12}{7} + \frac{- 3 c}{7}$

Divide $y$ by $1$ .

$y = \frac{12}{7} + \frac{- 3 c}{7}$

Move the negative in front of the fraction.

$y = \frac{12}{7} - \frac{3 c}{7}$

Solve for y 3c+7y=12

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