Solve for y 4(y+3)+7=3

$4 (y + 3) + 7 = 3$

Simplify $4 (y + 3) + 7$ .

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Simplify each term.

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Apply the distributive property.

$4 y + 4 \cdot 3 + 7 = 3$

Multiply $4$ by $3$ .

$4 y + 12 + 7 = 3$

Add $12$ and $7$ .

$4 y + 19 = 3$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $19$ from both sides of the equation.

$4 y = 3 - 19$

Subtract $19$ from $3$ .

$4 y = - 16$

Divide each term by $4$ and simplify.

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Divide each term in $4 y = - 16$ by $4$ .

$\frac{4 y}{4} = \frac{- 16}{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 y}{4} = \frac{- 16}{4}$

Divide $y$ by $1$ .

$y = \frac{- 16}{4}$

Divide $- 16$ by $4$ .

$y = - 4$

Solve for y 4(y+3)+7=3

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