Solve for y 4y+8=12

$4 y + 8 = 12$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $8$ from both sides of the equation.

$4 y = 12 - 8$

Subtract $8$ from $12$ .

$4 y = 4$

Divide each term by $4$ and simplify.

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Divide each term in $4 y = 4$ by $4$ .

$\frac{4 y}{4} = \frac{4}{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 y}{4} = \frac{4}{4}$

Divide $y$ by $1$ .

$y = \frac{4}{4}$

Divide $4$ by $4$ .

$y = 1$

Solve for y 4y+8=12

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