Solve for y 6y-12-4y=16

$6 y - 12 - 4 y = 16$

Subtract $4 y$ from $6 y$ .

$2 y - 12 = 16$

Move all terms not containing $y$ to the right side of the equation.

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Add $12$ to both sides of the equation.

$2 y = 16 + 12$

Add $16$ and $12$ .

$2 y = 28$

Divide each term by $2$ and simplify.

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Divide each term in $2 y = 28$ by $2$ .

$\frac{2 y}{2} = \frac{28}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 y}{2} = \frac{28}{2}$

Divide $y$ by $1$ .

$y = \frac{28}{2}$

Divide $28$ by $2$ .

$y = 14$

Solve for y 6y-12-4y=16

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