Solve for y a-3y=y+7

$a - 3 y = y + 7$

Move all terms containing $y$ to the left side of the equation.

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Subtract $y$ from both sides of the equation.

$a - 3 y - y = 7$

Subtract $y$ from $- 3 y$ .

$a - 4 y = 7$

Subtract $a$ from both sides of the equation.

$- 4 y = 7 - a$

Divide each term by $- 4$ and simplify.

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Divide each term in $- 4 y = 7 - a$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{7}{- 4} + \frac{- a}{- 4}$

Cancel the common factor of $- 4$ .

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Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{7}{- 4} + \frac{- a}{- 4}$

Divide $y$ by $1$ .

$y = \frac{7}{- 4} + \frac{- a}{- 4}$

Simplify each term.

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Move the negative in front of the fraction.

$y = - \frac{7}{4} + \frac{- a}{- 4}$

Dividing two negative values results in a positive value.

$y = - \frac{7}{4} + \frac{a}{4}$

Solve for y a-3y=y+7

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