Solve for y y^2-9y+20=0

Math
y2-9y+20=0
Factor y2-9y+20 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is 20 and whose sum is -9.
-5,-4
Write the factored form using these integers.
(y-5)(y-4)=0
(y-5)(y-4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
y-5=0
y-4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
y-5=0
Add 5 to both sides of the equation.
y=5
y=5
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
y-4=0
Add 4 to both sides of the equation.
y=4
y=4
The final solution is all the values that make (y-5)(y-4)=0 true.
y=5,4
Solve for y y^2-9y+20=0

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