Solve for z 2z^2-5z=1

Math
2z2-5z=1
Move 1 to the left side of the equation by subtracting it from both sides.
2z2-5z-1=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=2, b=-5, and c=-1 into the quadratic formula and solve for z.
5±(-5)2-4⋅(2⋅-1)2⋅2
Simplify.
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Simplify the numerator.
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Raise -5 to the power of 2.
z=5±25-4⋅(2⋅-1)2⋅2
Multiply 2 by -1.
z=5±25-4⋅-22⋅2
Multiply -4 by -2.
z=5±25+82⋅2
Add 25 and 8.
z=5±332⋅2
z=5±332⋅2
Multiply 2 by 2.
z=5±334
z=5±334
The final answer is the combination of both solutions.
z=5+334,5-334
The result can be shown in multiple forms.
Exact Form:
z=5+334,5-334
Decimal Form:
z=2.68614066…,-0.18614066…
Solve for z 2z^2-5z=1

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