Solve for z 4(3z+20)=12z+80

Math
4(3z+20)=12z+80
Simplify 4(3z+20).
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Apply the distributive property.
4(3z)+4⋅20=12z+80
Multiply.
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Multiply 3 by 4.
12z+4⋅20=12z+80
Multiply 4 by 20.
12z+80=12z+80
12z+80=12z+80
12z+80=12z+80
Move all terms containing z to the left side of the equation.
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Subtract 12z from both sides of the equation.
12z+80-12z=80
Combine the opposite terms in 12z+80-12z.
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Subtract 12z from 12z.
0+80=80
Add 0 and 80.
80=80
80=80
80=80
Since 80=80, the equation will always be true for any value of z.
All real numbers
The result can be shown in multiple forms.
All real numbers
Interval Notation:
(-∞,∞)
Solve for z 4(3z+20)=12z+80

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