Evaluate 100(1+0.08/12)^-48

$100 {(1 + \frac{0.08}{12})}^{- 48}$

Divide $0.08$ by $12$ .

$100 {(1 + 0.00\overline{6})}^{- 48}$

Add $1$ and $0.00\overline{6}$ .

$100 \cdot {1.00\overline{6}}^{- 48}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$100 \cdot \frac{1}{{1.00\overline{6}}^{48}}$

Raise $1.00\overline{6}$ to the power of $48$ .

$100 \cdot \frac{1}{1.3756661}$

Divide $1$ by $1.3756661$ .

$100 \cdot 0.72692058$

Multiply $100$ by $0.72692058$ .

$72.69205802$

Evaluate 100(1+0.08/12)^-48

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