Evaluate (7+1)^(-2/3)

${(7 + 1)}^{- \frac{2}{3}}$

Add $7$ and $1$ .

$8^{- \frac{2}{3}}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{8^{\frac{2}{3}}}$

Simplify the denominator.

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Rewrite $8$ as $2^{3}$ .

$\frac{1}{{(2^{3})}^{\frac{2}{3}}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{2^{3 (\frac{2}{3})}}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{1}{2^{3 (\frac{2}{3})}}$

Rewrite the expression.

$\frac{1}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{1}{4}$

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{4}$

Decimal Form:

$0.25$

Evaluate (7+1)^(-2/3)

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