Factor 49q^2-36 - Math help

Math

$49 q^{2} - 36$

Rewrite $49 q^{2}$ as ${(7 q)}^{2}$ .

${(7 q)}^{2} - 36$

Rewrite $36$ as $6^{2}$ .

${(7 q)}^{2} - 6^{2}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 7 q$ and $b = 6$ .

$(7 q + 6) (7 q - 6)$

Factor 49q^2-36

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