# Find the Variance -64 , 8 -64 , 8
The mean of a set of numbers is the sum divided by the number of terms.
x&OverBar;=-64+82
Cancel the common factor of -64+8 and 2.
Factor 2 out of -64.
x&OverBar;=2⋅-32+82
Factor 2 out of 8.
x&OverBar;=2⋅-32+2⋅42
Factor 2 out of 2⋅-32+2⋅4.
x&OverBar;=2⋅(-32+4)2
Cancel the common factors.
Factor 2 out of 2.
x&OverBar;=2⋅(-32+4)2(1)
Cancel the common factor.
x&OverBar;=2⋅(-32+4)2⋅1
Rewrite the expression.
x&OverBar;=-32+41
Divide -32+4 by 1.
x&OverBar;=-32+4
x&OverBar;=-32+4
x&OverBar;=-32+4
Add -32 and 4.
x&OverBar;=-28
Set up the formula for variance. The variance of a set of values is a measure of the spread of its values.
s2=∑i=1n⁡(xi-xavg)2n-1
Set up the formula for variance for this set of numbers.
s=(-64+28)2+(8+28)22-1
Simplify the result.
Simplify the numerator.
Add -64 and 28.
s=(-36)2+(8+28)22-1
Raise -36 to the power of 2.
s=1296+(8+28)22-1
Add 8 and 28.
s=1296+3622-1
Raise 36 to the power of 2.
s=1296+12962-1
Add 1296 and 1296.
s=25922-1
s=25922-1
Simplify the expression.
Subtract 1 from 2.
s=25921
Divide 2592 by 1.
s=2592
s=2592
s=2592
Approximate the result.
s2≈2592
Find the Variance -64 , 8

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