Solve for f 5/12f-25=0

$\frac{5}{12} f - 25 = 0$

Combine $\frac{5}{12}$ and $f$ .

$\frac{5 f}{12} - 25 = 0$

Add $25$ to both sides of the equation.

$\frac{5 f}{12} = 25$

Multiply both sides of the equation by $\frac{12}{5}$ .

$\frac{12}{5} \cdot \frac{5 f}{12} = \frac{12}{5} \cdot 25$

Simplify both sides of the equation.

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Simplify $\frac{12}{5} \cdot \frac{5 f}{12}$ .

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Cancel the common factor of $12$ .

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Cancel the common factor.

$\frac{12}{5} \cdot \frac{5 f}{12} = \frac{12}{5} \cdot 25$

Rewrite the expression.

$\frac{1}{5} \cdot (5 f) = \frac{12}{5} \cdot 25$

Cancel the common factor of $5$ .

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Factor $5$ out of $5 f$ .

$\frac{1}{5} \cdot (5 (f)) = \frac{12}{5} \cdot 25$

Cancel the common factor.

$\frac{1}{5} \cdot (5 f) = \frac{12}{5} \cdot 25$

Rewrite the expression.

$f = \frac{12}{5} \cdot 25$

Simplify $\frac{12}{5} \cdot 25$ .

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Cancel the common factor of $5$ .

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Factor $5$ out of $25$ .

$f = \frac{12}{5} \cdot (5 (5))$

Cancel the common factor.

$f = \frac{12}{5} \cdot (5 \cdot 5)$

Rewrite the expression.

$f = 12 \cdot 5$

Multiply $12$ by $5$ .

$f = 60$

Solve for f 5/12f-25=0

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