Solve for n 20(n+7)=4(35+5n)

Math
20(n+7)=4(35+5n)
Simplify 20(n+7).
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Apply the distributive property.
20n+20⋅7=4(35+5n)
Multiply 20 by 7.
20n+140=4(35+5n)
20n+140=4(35+5n)
Simplify 4(35+5n).
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Apply the distributive property.
20n+140=4⋅35+4(5n)
Multiply.
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Multiply 4 by 35.
20n+140=140+4(5n)
Multiply 5 by 4.
20n+140=140+20n
20n+140=140+20n
20n+140=140+20n
Move all terms containing n to the left side of the equation.
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Subtract 20n from both sides of the equation.
20n+140-20n=140
Combine the opposite terms in 20n+140-20n.
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Subtract 20n from 20n.
0+140=140
Add 0 and 140.
140=140
140=140
140=140
Since 140=140, the equation will always be true for any value of n.
All real numbers
The result can be shown in multiple forms.
All real numbers
Interval Notation:
(-∞,∞)
Solve for n 20(n+7)=4(35+5n)

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