Solve for t 4(t-2)-(t+2)=5

$4 (t - 2) - (t + 2) = 5$

Simplify $4 (t - 2) - (t + 2)$ .

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Simplify each term.

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Apply the distributive property.

$4 t + 4 \cdot - 2 - (t + 2) = 5$

Multiply $4$ by $- 2$ .

$4 t - 8 - (t + 2) = 5$

Apply the distributive property.

$4 t - 8 - t - 1 \cdot 2 = 5$

Multiply $- 1$ by $2$ .

$4 t - 8 - t - 2 = 5$

Simplify by adding terms.

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Subtract $t$ from $4 t$ .

$3 t - 8 - 2 = 5$

Subtract $2$ from $- 8$ .

$3 t - 10 = 5$

Move all terms not containing $t$ to the right side of the equation.

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Add $10$ to both sides of the equation.

$3 t = 5 + 10$

Add $5$ and $10$ .

$3 t = 15$

Divide each term by $3$ and simplify.

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Divide each term in $3 t = 15$ by $3$ .

$\frac{3 t}{3} = \frac{15}{3}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 t}{3} = \frac{15}{3}$

Divide $t$ by $1$ .

$t = \frac{15}{3}$

Divide $15$ by $3$ .

$t = 5$

Solve for t 4(t-2)-(t+2)=5

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