Solve for u u^2-8u+15=0

$u^{2} - 8 u + 15 = 0$

Factor $u^{2} - 8 u + 15$ using the AC method.

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Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $15$ and whose sum is $- 8$ .

$- 5, - 3$

Write the factored form using these integers.

$(u - 5) (u - 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$u - 5 = 0$

$u - 3 = 0$

Set the first factor equal to $0$ and solve.

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Set the first factor equal to $0$ .

$u - 5 = 0$

Add $5$ to both sides of the equation.

$u = 5$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$u - 3 = 0$

Add $3$ to both sides of the equation.

$u = 3$

The final solution is all the values that make $(u - 5) (u - 3) = 0$ true.

$u = 5, 3$

Solve for u u^2-8u+15=0

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