Solve for v v^2-2v-7=0

Math
v2-2v-7=0
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Substitute the values a=1, b=-2, and c=-7 into the quadratic formula and solve for v.
2±(-2)2-4⋅(1⋅-7)2⋅1
Simplify.
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Simplify the numerator.
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Raise -2 to the power of 2.
v=2±4-4⋅(1⋅-7)2⋅1
Multiply -7 by 1.
v=2±4-4⋅-72⋅1
Multiply -4 by -7.
v=2±4+282⋅1
Add 4 and 28.
v=2±322⋅1
Rewrite 32 as 42⋅2.
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Factor 16 out of 32.
v=2±16(2)2⋅1
Rewrite 16 as 42.
v=2±42⋅22⋅1
v=2±42⋅22⋅1
Pull terms out from under the radical.
v=2±422⋅1
v=2±422⋅1
Multiply 2 by 1.
v=2±422
Simplify 2±422.
v=1±22
v=1±22
The final answer is the combination of both solutions.
v=1+22,1-22
The result can be shown in multiple forms.
Exact Form:
v=1+22,1-22
Decimal Form:
v=3.82842712…,-1.82842712…
Solve for v v^2-2v-7=0

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