Solve for w (2+w)=w^2+(w+1)

Math
(2+w)=w2+(w+1)
Since w is on the right side of the equation, switch the sides so it is on the left side of the equation.
w2+w+1=2+w
Move all terms containing w to the left side of the equation.
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Subtract w from both sides of the equation.
w2+w+1-w=2
Combine the opposite terms in w2+w+1-w.
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Subtract w from w.
w2+0+1=2
Add w2 and 0.
w2+1=2
w2+1=2
w2+1=2
Move all terms not containing w to the right side of the equation.
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Subtract 1 from both sides of the equation.
w2=2-1
Subtract 1 from 2.
w2=1
w2=1
Take the square root of both sides of the equation to eliminate the exponent on the left side.
w=±1
The complete solution is the result of both the positive and negative portions of the solution.
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Any root of 1 is 1.
w=±1
The complete solution is the result of both the positive and negative portions of the solution.
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First, use the positive value of the ± to find the first solution.
w=1
Next, use the negative value of the ± to find the second solution.
w=-1
The complete solution is the result of both the positive and negative portions of the solution.
w=1,-1
w=1,-1
w=1,-1
Solve for w (2+w)=w^2+(w+1)

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